The product of two Dirac-level four-vectors is even: C = AB = s𝟙 + cα·α + cΣ·Σ, a scalar and two bivectors. Multiplying it from the left by a third vector D = d0β0 + d·β gives the triple product E = D(AB), which is odd: it fills the vector channels βμ and the pseudovector channels β̃μ, and nothing else. Choose D, A and B from the four-vectors used in the BQ papers.
No time adjoint is used at the Dirac level. D stands to the left of C throughout, so when D = ∂ its derivatives act on the channels of C.
With D = [[0, D], [−DT, 0]] and C = diag(−ABT, −ATB), the triple product is block off-diagonal:
The upper-right block is minus the BQ-Pauli triple product E = D(ATB). Reading the channels gives [E]β0 = −eT, [E]β = −eK, [E]β̃0 = e1, [E]β̃ = eσ: the four Pauli channel structures, with the Pauli minquat (T̂, K̂) mapped to the vectors and the pauliquat (1̂, σ̂) to the pseudovectors.
Named channels. Where the papers name the channels of C the page uses those names: b1, E/c and B for ∂A; −L, S and T for JA; S, M and L for RP; −𝓛, Tσ and TK for UG; σE, −Π/c and Ω for ∂G. Otherwise s, cα and cΣ.
Maxwell, Lorentz force and fluid products from de Haas (2026), BQ-Weyl electromagnetism, eqs. 90–113 and 397–409. Channels are derived symbolically in the page and checked numerically from the explicit matrices. Part of the BQ algebra at the Dirac level; the Pauli version is the BQ triple product explorer.